Remove spaces from a stringTag(s): String/Number
Remove all spaces
public String removeSpaces(String s) {
StringTokenizer st = new StringTokenizer(s," ",false);
String t="";
while (st.hasMoreElements()) t += st.nextElement();
return t;
}
[JDK1.5]
The String trim() method returns a copy of the string, with leading and trailing whitespace omitted.
ref : http://java.sun.com/j2se/1.5.0/docs/api/java/lang/String.html#trim()
[JDK1.4]
Here a complete solution to remove leading or trailing spaces in a String using regular expressions.
public class BlankRemover {
private BlankRemover () {}
/* remove leading whitespace */
public static String ltrim(String source) {
return source.replaceAll("^\\s+", "");
}
/* remove trailing whitespace */
public static String rtrim(String source) {
return source.replaceAll("\\s+$", "");
}
/* replace multiple whitespaces between words with single blank */
public static String itrim(String source) {
return source.replaceAll("\\b\\s{2,}\\b", " ");
}
/* remove all superfluous whitespaces in source string */
public static String trim(String source) {
return itrim(ltrim(rtrim(source)));
}
public static String lrtrim(String source){
return ltrim(rtrim(source));
}
public static void main(String[] args){
String oldStr =
"------[1-2-1-2-1-2-1-2-1-2-1-----2-1-2-1-2-1-2-1-2-1-2-1-2]----";
String newStr = oldStr.replaceAll("-", " ");
System.out.println(newStr);
System.out.println("*" + BlankRemover.ltrim(newStr) + "*");
System.out.println("*" + BlankRemover.rtrim(newStr) + "*");
System.out.println("*" + BlankRemover.itrim(newStr) + "*");
System.out.println("*" + BlankRemover.lrtrim(newStr) + "*");
}
/*
output :
[1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2]
*[1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2] *
* [1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2]*
* [1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2] *
*[1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2]*
*/
}